Answer:
The distance between (5, -8) and (5,2) is: d = 10 units
Explanation:
Note: I will solve the first question as the procedure solution for the remaining questions is exactly the same.
Given the points
Determining the distance between (5, -8) and (5,2)
![d=√(\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/43nekpf22oo7algepty78cen6ul22kgbzx.png)
substitute (x₁, y₁) = (2, 3) and (x₂, y₂) = (2, -5)
![=√(\left(5-5\right)^2+\left(2-\left(-8\right)\right)^2)](https://img.qammunity.org/2022/formulas/mathematics/college/sb47znuzbv6yhwup9lnosfjd7iqnnjlnf2.png)
![=√(\left(5-5\right)^2+\left(2+8\right)^2)](https://img.qammunity.org/2022/formulas/mathematics/college/l3n4wne9nek86hy4ve3mi0htlpjdsmp0fs.png)
![=√(0+10^2)](https://img.qammunity.org/2022/formulas/mathematics/college/lkxxdgnuiznxvzus82j2frw0ejg7aj8vao.png)
![=√(10^2)](https://img.qammunity.org/2022/formulas/mathematics/college/45oq83817ih3ityhiazlte6psv1fm86vgn.png)
units
Therefore, the distance between (5, -8) and (5,2) is: d = 10 units