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Find the area and perimeter

Find the area and perimeter-example-1

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Answer:

Area = 6a^4

Perimeter = 12a^2

Explanation:

from the measurements and from the figure it is a right triangle (triple of Pythagoras 3-4-5)

Area = 1/2 b × h

Area = 1/2 3a² × 4a²

Area = 1/2
12a^(4)

Area =
6a^(4)

----------------------------------

Perimeter

find the hypotenuse

by the rule of Pythagorean triples it is 5a²

so

3a² + 4a² + 5a² =

12a² (perimeter)

User VTi
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