Answer:
Let's use algebra to solve the problem.
Let x be the first number.
Let y be the second number.
From the problem, we can set up two equations:
"One number is less than 3 times another":
x = 3y - - - (Equation 1)
"Their sum is increased by 5 the result is 25":
x + y + 5 = 25
x + y = 20 - - - (Equation 2)
Now we have two equations with two unknowns. We can use substitution or elimination to solve for one of the variables.
Using substitution:
From equation 1, we know that x = 3y. We can substitute this into equation 2 to eliminate x:
3y + y = 20
4y = 20
y = 5
Now we can substitute this value of y back into equation 1 to find x:
x = 3y
x = 3(5)
x = 15
Therefore, the first number is 15 and the second number is 5.