Answer:
Explanation:
a= first form a equation
lets call the cheese c and the buns b
2c+3b=10
c=2+b
3c+4b=12
now its a simultaneous equation
2c+3b=10 x3
3c+4b=12 x2
6c+9b=30
6c+8b=24
1b=6
b=6
now substitute it in to 2c+3b=10
2c+18=10
2c+-8
so c=$4
b= 56 difference 14
56/2=28
28-7
21
28+7=35
so the 2 numbers are 21 and 35