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Area of quadrant of a circle with side 8cm and base 6cm​

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Answer:

A = (1/4)πr^2

where r is the radius of the circle.

If the side and base mentioned in the question refer to the radius of the circle, then the area of the quadrant can be calculated as follows:

Given, radius (r) = 8 cm

The area of the quadrant = (1/4)πr^2

= (1/4)π(8)^2

= 16π square cm

= 50.27 square cm

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