Question

Need help with This Math ​

Answer 1

Explanation:

Firstly,

angles at the centre of a circle add to 360°. So

`(15x-1)+\angle ZVX +(8x-2)+(7x+15)+(3x+5)=360`

`33x+17+\angle ZVX=360`

`\angle ZVX=360-33x-17`

`\angle ZVX=342-33x`

Secondly,

`\angle YVU+ \angle UVW + \angle WVX =180`° (since YX is a diameter - angles on a

straight line sum to 180°)

`(3x+5)+(7x+15)+(8x-2)=180`

`18x+18=180`

`18x=162`

`x=9`

Substitute
`x=9` into
`\angle ZVX=342-33x`:

`\angle ZVX=342-33*9=63`°

Solution:
`\angle ZVX=63`