225k views
2 votes
Solve the following equations . a² = 64. 2x-2 = 16. 3y² = 27​

User Apeiros
by
7.2k points

1 Answer

6 votes

Answer:

-3

Explanation:

a² = 64

Taking the square root of both sides, we get:

a = ±√64

a = ±8

Therefore, the solutions to the equation a² = 64 are a = 8 and a = -8.

2x-2 = 16

Adding 2 to both sides, we get:

2x = 18

Dividing both sides by 2, we get:

x = 9

Therefore, the solution to the equation 2x-2 = 16 is x = 9.

3y² = 27

Dividing both sides by 3, we get:

y² = 9

Taking the square root of both sides, we get:

y = ±√9

y = ±3

Therefore, the solutions to the equation 3y² = 27 are y = 3 and y = -3.

User Dezza
by
7.3k points