Question

For all the reactions, identify the reaction type and name the products formed.

1) Draw (Name) 5 structural isomers of pentene

2) Provide the balanced chemical equation for the complete combustion of propan-2-ol

3) 2 moles of Fluorine gas react with 2-methylpropane (provide at least two structural isomers)

4) 4-methylpent-1-ene reacts with hydrogen bromide (identify major and minor products if necessary)

5) Reaction of 2-methylpropan-1-ol with acidified potassium permanganate

6) Reaction of butan-2-ol with acidified potassium permanganate

7) Reaction of pentan-3-one with NaAlB4


8) Reaction between ethanol and ethanoic acid.


9) Name the reactants needed to prepare propyl ethanoate. Write an equation to show the reaction

10) Provide the equation for the hydrolysis of propyl propanoate.


11) Provide the equation for the hydrolysis N, N-dimethyl propanamide


12) How would you prepare ethoxyethane from ethene? Provide equations/reactions


13) How would you prepare propanoic acid from prop-1-ene? Provide equations/reactions

14) Place the following organic molecules in order of increasing boiling points: butane, butan-2-one, butanoic acid, and butan-2-ol. Justify your answer.

50 POINTS PLEASE BE ACCURATE AND CORRECT

Answer 1

1. Structural isomers of pentene:
a) 1-pentene
b) 2-pentene
c) 3-methyl-1-butene
d) 2-methyl-1-butene
e) 2-methyl-2-butene

2. Balanced chemical equation for the complete combustion of propan-2-ol:
C3H8O + 5O2 → 3CO2 + 4H2O

3. Two possible structural isomers of 2-methylpropane:
a) 2-methylbutane
b) 2,2-dimethylpropane

The reaction equation between 2 moles of Fluorine gas and 2-methylpropane is:
C4H10 + 10F2 → 4CF4 + 10HF

4. The reaction between 4-methylpent-1-ene and hydrogen bromide gives two major products:

2-bromo-4-methylpentane and 3-bromo-4-methylpentane.

5. Reaction of 2-methylpropan-1-ol with acidified potassium permanganate will produce 2-methylpropanal.

6. Reaction of butan-2-ol with acidified potassium permanganate will produce butan-2-one.

7. Reaction of pentan-3-one with NaAlH4 will produce pentan-3-ol.

8. The reaction between ethanol and ethanoic acid will produce ethyl ethanoate and water. The reaction is an esterification reaction.

9. Reactants needed to prepare propyl ethanoate are propanol and ethanoic acid. The reaction equation is:

C3H7OH + CH3COOH → C5H10O2 + H2O

10. The hydrolysis of propyl propanoate will produce propanoic acid and propanol. The reaction equation is:
C3H5C2H5O2 + H2O → C3H5COOH + C2H5OH

11. The hydrolysis of N, N-dimethyl propanamide will produce propanoic acid and dimethylamine. The reaction equation is:
(CH3)2NC2H5O + H2O → CH3COOH + (CH3)2NH

12. Ethoxyethane can be prepared from ethene through the reaction of ethene with ethanol in the presence of sulfuric acid. The reaction equation is:
C2H4 + C2H5OH → C4H10O

13. Propanoic acid can be prepared from prop-1-ene through the reaction of prop-1-ene with potassium permanganate followed by hydrolysis. The reaction equations are:
C3H6 + 2KMnO4 + 2H2SO4 → 3CH3COOH + 2MnSO4 + K2SO4 + 2H2O
CH3COOH + H2O → C2H5COOH

14. The increasing order of boiling points of the given organic molecules is:
butane < butan-2-ol < butan-2-one < butanoic acid.
The reason behind this order is that boiling point depends on the intermolecular forces between molecules, which are influenced by molecular weight and functional groups. Butane has only van der Waals forces, while butan-2-ol has hydrogen bonding in addition to van der Waals forces. Butan-2-one has a polar carbonyl group, which increases the dipole-dipole interactions. Butanoic