Answer:
Let the cost to supply 10% of the bins be X dollars.
To find the cost of supplying bins to 50% of the cost to supply 10%, we can set up the following proportion:
10% of the cost = X dollars
50% of the cost = Y dollars
We know that the two costs are proportional, so we can set up the following equation:
10% / 50% = X / Y
Simplifying this equation, we get:
0.1 / 0.5 = X / Y
0.2 = X / Y
Multiplying both sides by Y, we get:
Y * 0.2 = X
Y = X / 0.2
Y = 5X
Therefore, the cost of supplying bins to 50% of the cost to supply 10% is 5 times the cost of supplying bins to 10%.
Substituting X = C/10 (where C is the cost to supply 10% of the bins), we get:
Y = 5X = 5(C/10) = C/2
So the cost of supplying bins to 50% of the cost to supply 10% is C/2 dollars.
To find the cost of supplying bins to 85% of the cost to supply 10%, we can set up a similar proportion:
10% of the cost = X dollars
85% of the cost = Z dollars
We know that the two costs are proportional, so we can set up the following equation:
10% / 85% = X / Z
Simplifying this equation, we get:
0.1 / 0.85 = X / Z
0.1176 = X / Z
Multiplying both sides by Z, we get:
Z * 0.1176 = X
Z = X / 0.1176
Z = 8.5X
Therefore, the cost of supplying bins to 85% of the cost to supply 10% is 8.5 times the cost of supplying bins to 10%.
Substituting X = C/10 (where C is the cost to supply 10% of the bins), we get:
Z = 8.5X = 8.5(C/10) = 0.85C
So the cost of supplying bins to 85% of the cost to supply 10% is 85% of the cost to supply 10%, or 0.85C dollars.
Therefore, the costs of supplying bins to 10%, 50%, and 85% of the cost to supply 10% are:
- 10% of the cost: X dollars = C/10 dollars
- 50% of the cost: Y dollars = C/2 dollars
- 85% of the cost: Z dollars = 0.85C dollars