Answer:
Let x be the price of one adult ticket, and y be the price of one student ticket.
From the information given in the problem, we can set up the following system of equations:
15x + 5y = 265 (equation 1)
15x + 16y = 419 (equation 2)
We can solve for x by subtracting equation 1 from equation 2:
15x + 16y - (15x + 5y) = 419 - 265
11y = 154
y = 14
Now we can substitute y = 14 into either equation 1 or equation 2 to solve for x. Let's use equation 1:
15x + 5(14) = 265
15x + 70 = 265
15x = 195
x = 13
Therefore, one adult ticket costs $13, and one student ticket costs $14.