Answer:
The height of Moyo is
![(67)/(6)](https://img.qammunity.org/2022/formulas/mathematics/high-school/emmk3n6vtd5tvj82d1q4sqk54fjdgiktoa.png)
The height of Adamu is
![(13)/(6)](https://img.qammunity.org/2022/formulas/mathematics/high-school/1i5wqhcos67cpigodv0piqjw0sodmmwfsc.png)
Explanation:
Equations
To solve the problem, we assign the variable:
x = height of Moyo
Since Moyo is 9 units taller than Adamu:
x - 9 = height of Adamu
The difference of the squares of their heights is 120, thus:
![x^2-(x - 9)^2=120](https://img.qammunity.org/2022/formulas/mathematics/high-school/u780w35etxi6n1gukz9tci472kw08cordp.png)
Operating:
![x^2-(x^2-18x+81)=120](https://img.qammunity.org/2022/formulas/mathematics/high-school/d7u1h6ybgydvrq2vgrw25vovwvry16l0di.png)
![x^2-x^2+18x-81=120](https://img.qammunity.org/2022/formulas/mathematics/high-school/22930m5t6ulys34b9fgb83uiy1jcf2ix8y.png)
Simplifying:
![18x-81=120](https://img.qammunity.org/2022/formulas/mathematics/high-school/pustuco9qfxrfi1t82kwpzbvnvmpfegsbb.png)
Adding 81:
![18x=120+81=201](https://img.qammunity.org/2022/formulas/mathematics/high-school/vut2szindkxqhjkn710wfm5qub18oqhdfl.png)
Dividing by 18:
![x=(201)/(18)=(67)/(6)](https://img.qammunity.org/2022/formulas/mathematics/high-school/u9futqzjepm8nsp21t53clkhe1e8kyjyn3.png)
The height of Moyo is
![(67)/(6)](https://img.qammunity.org/2022/formulas/mathematics/high-school/emmk3n6vtd5tvj82d1q4sqk54fjdgiktoa.png)
The height of Adamu is
![(67)/(6)-9=(13)/(6)](https://img.qammunity.org/2022/formulas/mathematics/high-school/tqholdthrtn61j3qzq9tknjbdzdnxd0dtp.png)