so hmm the reply above is very nice by "2023Kl" for 2)
let's poke the one before 2)
J = Jar of cottage cheese price
B = Buns of bread price
so two J and three B cost €10, that means 2J + 3B = 10.
we also know that one J is €2 more than a B, so J = B + 2.
![J=B+2 \\\\[-0.35em] ~\dotfill\\\\ 2J+3B=10\implies \stackrel{\textit{substituting from above}}{2(B+2)+3B=10}\implies 2B+4+3B=10 \\\\\\ 5B+4=10\implies 5B=6\implies B=\cfrac{6}{5}\implies \boxed{B=1.2} \\\\\\ J=B+2\implies J=\cfrac{6}{5}+2\implies J=\cfrac{6+10}{5}\implies J=\cfrac{16}{5}\implies \boxed{J=3.2}](https://img.qammunity.org/2024/formulas/mathematics/high-school/p666zuu7zsz9szwr2nnnlubhh8o5r6tbq3.png)