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Point D is the centroid of ∆ABC, DC = 8x - 6, and ED = 3x + 2. What is CE?​

Point D is the centroid of ∆ABC, DC = 8x - 6, and ED = 3x + 2. What is CE?​-example-1

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Answer:

See below.

Explanation:

For this problem, we are asked to solve for CE.

Because Point D is a Centroid, CE is a median.

What is a Median?

A Median is a line that connects from 1 vertex of a Triangle, through the Centroid, and then ending on the midpoint of the opposite side.

The distance from the Triangles' Vertex to the Centroid is 2 times the distance from the Centroid to the Midpoint.

Basically;


ED = (1)/(2) CD

Let's solve for x first.


3x+2=(1)/(2) (8x-6)

Distribute:


3x+2=4x-3

Subtract 4x from both sides:


-x+2=-3

Subtract 2 from both sides:


-x=-5

Divide by -1:


x=5.

CD, and DE are 2 parts of CE. When we add CD, and DE together we will have the value of CE.


CD+DE=CE.

Let's identify CD and DE first since we have the value of x.


CD=8(5)-6=34.


DE=3(5)+2=17.

Add:


34+17=51 \ (CE)

Our final answer is D, CE = 51.

User Danny C
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