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If a perimetre of a rectangle is 38 cm and length is 12.5 cm What is the Area?

User Cubrman
by
6.7k points

2 Answers

5 votes

Answer:

81.25 cm^2

Explanation:

perimeter = 2(l + w)

2(12.5 + w) = 38

12.5 + w = 38/2

w = 19 - 12.5

w = 6.5

Area = lw = 12.5 x 6.5 = 81.25

User Zombi
by
6.6k points
1 vote

Answer:

81.25 cm²

Explanation:

What is the area?

The area is the total space taken up by a flat (2-D) surface or shape. The area is always measured in square units.

To solve for the perimeter of a rectangle, the expression is:

(Let p = perimeter, l = length, w = width)

  • (l × 2) + (w × 2) = p

To solve for the width of a rectangle when given the perimeter, we can use this expression:

  • (p - [l × 2]) ÷ 2 = w

Inserting 38 in for 'p' and 12.5 for 'l':

  • (38 - [12.5 × 2]) ÷ 2 = 6.5

To check our work, we can use the expression to solve for the perimeter:

  • (6.5 × 2) + (12.5 × 2) = 38

Because the perimeter matches up with 38, we know the width of the rectangle is 6.5cm.

To solve for the area of a rectangle, we use this expression:

(Let a = area)

  • l × w = a

Inserting 12.5 in for 'l' and 6.5 in for 'w':

  • 12.5 × 6.5 = 81.25

Therefore, the area of the rectangle is 81.25 cm².

User Martin Rauscher
by
7.3k points