Answer:
the sum of a+b+c is 56.
Explanation:
If a:b:c = 1:3:4 and c = 28, we can find the values of a and b using the ratios.
Since a:b:c = 1:3:4, we can write:
a = x, b = 3x, c = 4x
where x is some constant of proportionality.
We are given that c = 28, so we can substitute this value to get:
4x = 28
Solving for x, we get:
x = 7
Therefore, a = x = 7 and b = 3x = 21.
The sum of a, b, and c is:
a + b + c = 7 + 21 + 28 = 56
So the sum of a+b+c is 56.