Question

How do you do this Maths question?

Answer 1

See below.

Explanation:

We are asked to simplify the given expression.

Let's begin by identifying an important rule. Because there's a negative exponent and a negative exponent outside of the parentheses, we multiply the exponents and the product will be a positive exponent.

We also need to remember that the exponent outside of the parentheses acts on everything inside the parentheses.

Evaluate:

`(2t^(-3) )^(-2) = 2^(-2) * t^(6).`

Further Evaluate:

`2^(-2) = (1)/(2^2) = (1)/(4). \\t^(6) = t * t * t * t * t * t.`

Multiply:

`t^(6) * (1)/(4) = (t^(6) )/(4) \ or \ (1)/(4) (t^6) .`

We can't simplify any further.

Therefore, our final answer is
`(t^(6) )/(4) \ or \ (1)/(4) (t^6).`

Answer 2

Explanation:

`we \ can \ show \\(a^(b))^(c)=a^(bc)\\,as,\\2^(-2)t^(6)\\a^(-b)=(1)/(a^(b))\\2^(-2)t^(6)=(1)/(4)t^(6)`