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High order thinking and assessment practice

HELP PLS

High order thinking and assessment practice HELP PLS-example-1
User Sloan
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2 Answers

3 votes

Answer:

10)

a) 5x + 5(11) = 120

b) x = 13

11) $392.50

12) Letter D

Explanation:

10:

5x + 5(11) = 120

5x + 55 = 120 Subtract 55 from both sides

5x + 55 - 55 = 120 - 55

5x = 65 Divide both sides by 5


(5x)/(5) =
(65)/(5)

x = 13

11:

Let j = Jason's earnings

Let k = Kevin's earnings

j = 212.50

k = 2j - 32.50

substitute 212.50 for j in the second equation and solve for k

k = 2(212.50)- 32.50

k = 425 - 32.50

k = 392.50

Kevin earned $392.50.

12:

18 =
(1)/(2) x + 6 Subtract 6 from both sides

18 - 6 =
(1)/(2) x + 6 - 6

12 =
(1)/(2) x Multiply both sides by 2

12(2) =
(1)/(2) x (
(2)/(1)) (
(2)/(1) is another name for 2)

24 = x

To solve we subtract 6 first and then multiply by 2. Letter D.

Helping in the name of Jesus.

User Nateowami
by
7.9k points
4 votes

High order thinking:

PART A:

If each friend buys 11 more action figures, then each will have x + 11 action figures. Since the total action figures is 120, we can write the equation:


5(x+11)=120

PART B:

Solve for x. Divide both sides by 5.


x+11=24

Substract 11 from both sides:


x=13\\

Each friend originally had 13 action figures each.

Assessment practice:

11: Let Kevin Earns X amount

So, Jason earns = 2x - 32.50

= 212.50

2x = 2120 x 50 +32.40 = 245.00/2

= 122.5

Answer: Kevin Earns $122.50

12: Subtract 6. Then multiply by 2.


(1)/(2) x+6=18\\\\(1)/(2)x = 18-6\\(1)/(2)x=12\\(1)/(2)x*2=12*2\\x=24

Thanks,
Eddie E.

User Lehs
by
9.2k points

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