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In a physics lab experiment, a 6kg box is pushed across a flat table by a horizontal force F . What the magnitude of force F if the box is speeding up with a constant acceleration of 0.18ms^-2?​

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Answer:

The F's accelerated

where m is the box's mass, an is its acceleration, and F net is the net force.

The net force in this situation is equal to the applied force less any potential frictional forces. The net force is just the force applied to the box, assuming the table is smooth and there is no friction:

F net = F

Thus, the equation can be rewritten as follows:

F = m * a

Inputting the values provided yields:

F = 6 kg times 0.18 m/s2 to get 1.08 N

As a result, 1.08 N of force F is needed to accelerate a 6 kilogramme box at a constant rate of 0.18 m/s2.

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