Question

Let A denote the event of placing a $1 straight bet on a certain lottery and winning. Suppose that, for this particular lottery, there are 2,352 different ways that you can select the four digits (with repetition allowed)

in this lottery, and only one of those four-digit numbers will be the winner. What is the value of P(A)? What is the value of P(A)?
What is the value of P(A)?
P(A)= (Round to five decimal places as needed.)
What is the value of P(A)?
P(A)=(Round to five decimal places as needed.)

Answer 1

The probability of winning the lottery, denoted by P(A), can be calculated as follows:

P(A) = number of winning outcomes / total number of possible outcomes

Since there is only one winning four-digit number and there are 2,352 possible four-digit numbers, we have:

P(A) = 1/2352

Using a calculator, we get:

P(A) ≈ 0.00042

Therefore, the value of P(A) is approximately 0.00042 or 4.2 × 10^(-4) (rounded to five decimal places).

Explanation: