Question

Solve the following system y=5x-33x-8y=24

Answer 1

The given system is

`\mleft\{\begin{aligned}y=5x-3 \\ 3x-8y=24\end{aligned}\mright.`

We can multiply the first equation by 8, then we sum and solve for x.

`\mleft\{\begin{aligned}8y=40x-24 \\ 3x-8y=24\end{aligned}\rightarrow3x=40x\mright.`

Then we, solve for x.

`\begin{gathered} 40x-3x=0 \\ 27x=0 \\ x=(0)/(27)=0 \end{gathered}`

Now we use this value to find y.

`\begin{gathered} 3x-8y=24 \\ 3(0)-8y=24 \\ -8y=24 \\ y=(24)/(-8)=-3 \end{gathered}`

Therefore, the solution of the system is x = 0 and y = -3.