Answer:
The objective of this study is to determine the duration of time it takes for an object with an initial velocity of 15 m.s-1 to reach its peak height and descend back to its starting point when launched straight upwards, such as when throwing a ball straight up into the air. The study takes into account the effects of gravity, air resistance and Newton's Laws of Motion.
For the purpose of this study, a mathematical investigation is undertaken, taking into consideration the initial velocity (vi = 15 m.s-1) and the gravitational acceleration (g = 9.81 m.s-2). The equation for the Time of Flight (T) is derived by using kinematic equations, as followed:
T = 2vi/g
Where T is the time of flight and vi is the initial velocity of the object.
In this case, the Time of Flight is equal to T = 2∙ 15m/s / 9.81 m/s2 = 3.03 s.
Therefore, when the ball is released into the air the ball was be in the air for 3.03 seconds before descending back to its starting point.
Friction, in this case, does not need to be included in the equations because it's negligible. However, to accurately determine the time the ball reaches its peak, additional equations should be used by considering the forces acting on the object, being drag, air resistance, and gravity