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1 vote
If 48.0 g of NaCl react with 19.0 g of H₂SO4, what mass of Na₂SO4 will be produced?

equation is
2NaCI + H2SO4--Na2SO4 + 2HCI​

1 Answer

6 votes

Answer: 355

Explanation: Given the molecular weights:

M

r

N

a

O

H

=

40

g

m

o

l

M

r

N

a

2

S

O

4

=

142

g

m

o

l

The analogy of the moles will be held constant:

n

N

a

O

H

n

N

a

2

S

O

4

=

2

1

n

N

a

O

H

n

N

a

2

S

O

4

=

2

For each one, substitute:

n

=

m

M

r

Therefore:

n

N

a

O

H

n

N

a

2

S

O

4

=

2

m

N

a

O

H

M

r

N

a

O

H

m

N

a

2

S

O

4

M

r

N

a

2

S

O

4

=

2

200

40

x

142

=

2

200

142

40

x

=

2

200

142

=

2

40

x

x

=

200

142

2

40

=

100

142

40

=

10

142

4

=

1420

4

=

=

710

2

Given the molecular weights:

M

r

N

a

O

H

=

40

g

m

o

l

M

r

N

a

2

S

O

4

=

142

g

m

o

l

The analogy of the moles will be held constant:

n

N

a

O

H

n

N

a

2

S

O

4

=

2

1

n

N

a

O

H

n

N

a

2

S

O

4

=

2

For each one, substitute:

n

=

m

M

r

Therefore:

n

N

a

O

H

n

N

a

2

S

O

4

=

2

m

N

a

O

H

M

r

N

a

O

H

m

N

a

2

S

O

4

M

r

N

a

2

S

O

4

=

2

200

40

x

142

=

2

200

142

40

x

=

2

200

142

=

2

40

x

x

=

200

142

2

40

=

100

142

40

=

10

142

4

=

1420

4

=

=

710

2

= 355 GMS

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