Answer:
To solve this problem, we need to use the formula:
distance = initial velocity x time + 1/2 x acceleration x time^2
where:
initial velocity = 72 km/hour (we need to convert this to m/s to use it in the formula)
time = 5 seconds
acceleration = 10 m/s^2 (assuming this is the acceleration due to gravity)
Converting the initial velocity from km/hour to m/s:
72 km/hour = (72 x 1000 m) / (60 x 60 s) = 20 m/s
Now we can plug in the values into the formula:
distance = 20 m/s x 5 s + 1/2 x 10 m/s^2 x (5 s)^2
distance = 100 m + 1/2 x 10 m/s^2 x 25 s^2
distance = 100 m + 125 m
distance = 225 meters
Therefore, the distance traveled by the bus in 5 seconds is 225 meters.