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A Camot engine works between the se and the sink with efficiency 40% How much perature of the sink be lowered keeping the source parature constant so that its efficiency increases by 10%?



User Swivel
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Answer:

if the temperature of the sink is lowered by 6.7%, the efficiency of the Carnot engine will increase by 10%.

Step-by-step explanation:

The efficiency of a Carnot engine is given by the equation:

η = 1 - T_sink / T_source

where η is the efficiency, T_sink is the temperature of the sink, and T_source is the temperature of the source.

In this case, we are given that the efficiency of the engine is 40%. Therefore, we can write:

0.4 = 1 - T_sink / T_source

Rearranging this equation, we get:

T_sink / T_source = 1 - 0.4

T_sink / T_source = 0.6

Next, we are asked to find the temperature of the sink needed to increase the efficiency of the engine by 10%. Let's call this new efficiency η_new. Since the efficiency of a Carnot engine is given by the same equation as before, we can write:

η_new = 1 - T_sink_new / T_source

where η_new is the new efficiency, and T_sink_new is the new temperature of the sink.

We know that the new efficiency is 10% higher than the original efficiency, so we can write:

η_new = η + 0.1η = 0.4 + 0.1(0.4) = 0.44

Substituting this into the equation above, we get:

0.44 = 1 - T_sink_new / T_source

Rearranging this equation, we get:

T_sink_new / T_source = 1 - 0.44

T_sink_new / T_source = 0.56

Now we can set up an equation to find the new temperature of the sink:

0.56 = T_sink_new / T_source

T_sink_new = 0.56T_source

To find the temperature difference between the old and new sink temperatures, we can subtract the two equations we have derived:

T_sink_new - T_sink = 0.6T_source - 0.56T_source

T_sink_new - T_sink = 0.04T_source

Finally, we can substitute the given efficiency of 40% to find the source temperature:

0.4 = 1 - T_sink / T_source

T_source = T_sink / (1 - 0.4)

T_source = T_sink / 0.6

Substituting this expression for T_source into the equation for the temperature difference, we get:

T_sink_new - T_sink = 0.04(T_sink / 0.6)

Simplifying, we get:

T_sink_new - T_sink = 0.067T_sink

Multiplying both sides by 100, we get:

(T_sink_new - T_sink) * 100 = 6.7T_sink

Therefore, if the temperature of the sink is lowered by 6.7%, the efficiency of the Carnot engine will increase by 10%.

User Nordhagen
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