Answer:
We can use the formula for the area of a triangle to solve for the height of the isosceles triangle, which will then allow us to find the lengths of the other two sides.
Let h be the height of the isosceles triangle, and let s be the length of each of the two equal sides. Then the area of the triangle is given by:
A = (1/2)bh = (1/2)(10m)(h) = 5h
We also know that the area of the triangle is 60 square meters, so we can set these two expressions equal to each other and solve for h:
5h = 60
h = 12
Now that we know the height of the triangle is 12 meters, we can use the Pythagorean theorem to find the length of each of the other two sides:
s^2 = h^2 + (1/2b)^2
s^2 = 12^2 + (5^2)
s^2 = 169
s = sqrt(169)
s = 13
Therefore, the lengths of the other two sides of the isosceles triangle are both 13 meters.