Question

in the hydrolysis of pcl3 what mass of HCl can be produced from 15.0g of pcl3the equation for the reaction is Pcl3 +3H2O-- 3HCL + H3PO3​

Answer 1

To solve this problem, we need to use stoichiometry.

From the balanced chemical equation, we can see that 1 mole of PCl3 produces 3 moles of HCl. Therefore, we need to first calculate the number of moles of PCl3 in 15.0 g:

moles of PCl3 = mass / molar mass
moles of PCl3 = 15.0 g / 137.33 g/mol
moles of PCl3 = 0.109 mol

Now, we can use the mole ratio from the balanced chemical equation to find the number of moles of HCl produced:

moles of HCl = moles of PCl3 x (3 moles of HCl / 1 mole of PCl3)
moles of HCl = 0.109 mol x 3
moles of HCl = 0.327 mol

Finally, we can use the molar mass of HCl to convert the number of moles to mass:

mass of HCl = moles of HCl x molar mass
mass of HCl = 0.327 mol x 36.46 g/mol
mass of HCl = 11.9 g

Therefore, 15.0 g of PCl3 can produce 11.9 g of HCl.