Question

The product of two positive number is 108. If one one number is treble of other number, find those number​

Answer 1

Let's call the smaller number "x". Since the larger number is treble the smaller number, we can call it "3x". We know that the product of these two numbers is 108, so we can set up an equation:

x * 3x = 108

Simplifying the left side of the equation:

3x^2 = 108

Dividing both sides by 3:

x^2 = 36

Taking the square root of both sides:

x = 6

Since the smaller number is 6, we can find the larger number by multiplying it by 3:

3x = 3(6) = 18

Therefore, the two numbers are 6 and 18.

Answer 2

Let's assume that the smaller of the two positive numbers is x. Then we can express the larger number as 3x, since it is three times the smaller number.

We are given that the product of the two numbers is 108, so we can write:

x * 3x = 108

Simplifying this equation, we get:

3x^2 = 108

Dividing both sides by 3, we get:

x^2 = 36

Taking the square root of both sides, we get:

x = 6

Since x is the smaller of the two numbers, the larger number is 3x, which is:

3x = 3(6) = 18

Therefore, the two positive numbers are 6 and 18. We can check that their product is indeed 108:

6 * 18 = 108

So the solution is that the two positive numbers are 6 and 18.