Question

Problem 7.4 Two capacitors, each of capacitance 2 μF are connected in parallell. If the p.d. across them is 120V, calculate the charge on each capacitor.​

Answer 1

240 μC

Step-by-step explanation:

When two capacitors are connected in parallel, the effective capacitance is the sum of the individual capacitances. In this case, the effective capacitance is:

C = C1 + C2 = 2 μF + 2 μF = 4 μF

The charge on a capacitor is related to the capacitance and the potential difference across it by the equation:

Q = C × V

where Q is the charge, C is the capacitance, and V is the potential difference.

Using this equation, the charge on each capacitor can be calculated as follows:

Q1 = C1 × V = 2 μF × 120 V = 240 μC

Q2 = C2 × V = 2 μF × 120 V = 240 μC

Therefore, the charge on each capacitor is 240 μC.