Answer:222
Step-by-step explanation:The arithmetic series is given by:
a1 = 2, d=3, n = 12
where a1 is the first term, d is the common difference, and n is the number of terms.
To evaluate this series, we can use the formula for the sum of an arithmetic series:
Sn = n/2 * [2a1 + (n-1)d]
where Sn is the sum of the first n terms.
Substituting the given values, we get:
S12 = 12/2 * [2(2) + (12-1)(3)]
= 6 * [4 + 33]
= 6 * 37
= 222
Therefore, the sum of the first 12 terms of the arithmetic series with a1 = 2, d=3 is 222.