The correct answer is:
x + 12 ≤ 5 − y ≤ 2(x − 3)
Step-by-step explanation:
From the given inequalities:
x + 12 ≤ 5 − y ... (1)
5 − y ≤ 2(x − 3) ... (2)
We can see that 5 - y is common in both inequalities. We can isolate this term by subtracting 5 from both sides of (1) and (2):
x + 7 ≤ -y ... (3)
-y ≤ 2(x - 8) ... (4)
Multiplying (3) by -1, we get:
y - 7 ≥ x ... (5)
Substituting this value of x in (4), we get:
y - 7 ≤ -2(7 - y)
y - 7 ≤ -14 + 2y
y ≤ 7
Substituting this value of y in (5), we get:
0 ≤ x + 7 ≤ 14
Subtracting 7 from all sides, we get:
-7 ≤ x ≤ 7
Therefore, the statement x + 12 ≤ 5 − y ≤ 2(x − 3) is not true, but the statement -7 ≤ x ≤ 7 is true.