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Log4 n=1/4 log4 81 + 1/2 log4 25

Solve and show work

(I cannot for the life of me figure this one out, so please help me !!)

Log4 n=1/4 log4 81 + 1/2 log4 25 Solve and show work (I cannot for the life of me-example-1
User Edelagnier
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Answer:

Explanation:

We can start by using the logarithmic rule that states:

log a (mn) = log a (m) + log a (n)

And also the property:

log a (b^c) = c*log a (b)

With these rules, we can simplify the given expression as follows:

log4 n = 1/4 log4 81 + 1/2 log4 25

log4 n = log4 81^(1/4) + log4 25^(1/2) (using the above properties)

log4 n = log4 (3^4)^(1/4) + log4 (5^2)^(1/2) (81 = 3^4 and 25 = 5^2)

log4 n = log4 3 + log4 5 (using the rule log a (b^c) = c*log a (b))

log4 n = log4 (3*5) (using the rule log a (mn) = log a (m) + log a (n))

log4 n = log4 15

Therefore, the solution to the equation log4 n=1/4 log4 81 + 1/2 log4 25 is:

n = 15

User Lucas Oman
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