Question

Step 2: Show the conversions required to solve this problem and calculate the grams of Ni.

54.3 g Ni₂0, x
Incorrect
grams of Ni:
Incorrect
165.38 g Ni₂0,
1 mole 0₂
Answer Bank
1 mole Ni₂0,
3 moles O₂
58.69 g Ni
2 moles Ni₂0,
1 mole Ni
= g Ni
32.00 g 0₂
4 moles Ni
& Ni

Answer 1

To solve this problem and calculate the grams of Ni, we need to use the molar mass of Ni₂0₃ and the stoichiometry of the reaction.

The balanced chemical equation for the reaction between Ni₂0₃ and H₂ is:

Ni₂0₃ + 2H₂ → 2Ni + 3H₂0

From this equation, we can see that 1 mole of Ni₂0₃ reacts to produce 2 moles of Ni. Therefore, we can use the following conversion factor:

1 mole Ni₂0₃ = 2 moles Ni

We can also use the molar mass of Ni₂0₃ to convert grams of Ni₂0₃ to moles of Ni₂0₃:

54.3 g Ni₂0₃ x (1 mole Ni₂0₃ / 165.38 g Ni₂0₃) = 0.3284 moles Ni₂0₃

Now, we can use the conversion factor to find moles of Ni:

0.3284 moles Ni₂0₃ x (2 moles Ni / 1 mole Ni₂0₃) = 0.6568 moles Ni

Finally, we can use the molar mass of Ni to convert moles of Ni to grams of Ni:

0.6568 moles Ni x (58.69 g Ni / 1 mole Ni) = 38.53 g Ni

Therefore, the grams of Ni in 54.3 g Ni₂0₃ is 38.53 g Ni.

Step-by-step explanation: