Question

Macmillan Learning

Step 2: Show the conversions required to solve this problem and calculate the grams of Br₂.
70.6 g AlBr, x
grams of Br₂:
26.98 g Al
159.80 g Br₂
266.68 g AlBr,
Answer Bank
I mole Al
1 mole Br₂
1 mole AlBr,
2 moles Al
3 moles Br₂
2 moles AlBr,
= g Br₂
g Br₂

Answer 1

To solve the problem, we need to convert the given quantity of AlBr to grams of Br₂ using the given molar ratios:

70.6 g AlBr * (1 mole AlBr / 266.68 g AlBr) * (3 moles Br₂ / 2 moles AlBr) * (159.80 g Br₂ / 1 mole Br₂) = 94.3 g Br₂

Therefore, 94.3 g of Br₂ are required.