Question

If I leave 800 mL of 0.70 M sodium chloride solution uncovered on a windowsill and 300 mL of the solvent evaporates, what will the new concentration of the sodium chloride solution be?

Answer 1

the new concentration of the sodium chloride solution after 300 mL of solvent evaporates is 1.12 M.

Step-by-step explanation:

To calculate the new concentration of the sodium chloride solution after 300 mL of solvent evaporates, we need to first determine how many moles of solute are present in the original solution:

moles of solute = concentration x volume

moles of solute = 0.70 M x 0.800 L

moles of solute = 0.56 moles

Next, we can calculate the new volume of the solution after 300 mL evaporates:

new volume = original volume - amount evaporated

new volume = 0.800 L - 0.300 L

new volume = 0.500 L

Finally, we can calculate the new concentration of the solution using the moles of solute and the new volume:

new concentration = moles of solute / new volume

new concentration = 0.56 moles / 0.500 L

new concentration = 1.12 M

Therefore, the new concentration of the sodium chloride solution after 300 mL of solvent evaporates is 1.12 M.