To find the x-intercepts of the function h(x) = (x - 4)^2 - 1, we need to set h(x) equal to zero and solve for x:
0 = (x - 4)^2 - 1
Adding 1 to both sides, we get:
1 = (x - 4)^2
Taking the square root of both sides, we get:
±1 = x - 4
Adding 4 to both sides, we get:
x = 4 ± 1
Therefore, the x-intercepts of the function h(x) are (3, 0) and (5, 0).