Question

Some number are formed with closed paths. the digits 0, 4, 6, and 9 each have 1 closed path, and 8 has 2. None of the other numbers is formed with a closed path. Given a number, determine the total number of closed paths in all of its digits combined

Answer 1

To solve this problem, we need to count the number of closed paths in each digit of the given number and then add them up.

For digits 0, 4, 6, and 9, there is one closed path each. For digit 8, there are two closed paths. For all other digits, there are no closed paths.

So, to find the total number of closed paths in a given number, we need to count the number of occurrences of each digit and multiply it by the corresponding number of closed paths. Then we add up all the results.

For example, if the given number is 4698, we can count the number of occurrences of each digit as follows:

Digit 4 occurs once

Digit 6 occurs once

Digit 9 occurs once

Digit 8 occurs once

All other digits (1, 2, 3, 5, 7) do not have any closed paths.

So the total number of closed paths in the number 4698 is:

1 (for digit 4) + 1 (for digit 6) + 1 (for digit 9) + 2 (for digit 8) = 5

Therefore, the total number of closed paths in the number 4698 is 5.

Step-by-step explanation: