Given the function I need to evaluate question a)

Question

asked Oct 22, 2024 129k views

2 Answers

Beerbajay · Answer 1 · 2024-10-28T20:53:47+0000

Answer:

a) p(-6) = 30

b) c = -2 ,1

Explanation:

p(c)=c^2+c

a) Evaluate p(-6)

This mean input -6 into the equation to solve for p(-6) =

$p(-6)=(-6)^2+(-6)\\\\p(-6)=36-6\\\\p(-6)=30\\$

(b) Solve for p(c) = 2.

$p(c)=c^2+c\\\\2=c^2+c\\\\c^2+c=2\\\\c^2+c-2=0\\\\Factoring\\(c+2)(c-1)=0\\(c+2)=0,(c-1)=0\\c = -2 , 1$