Question

Pla help algebra1 pls

Answer 1

2(4a^3-49a) = 8a^3-98a
It’s basic distributive property. We multiply the 2 that’s outside the brackets by each term in the brackets. So (2x4a^3) - (2x98a) gives us 8a^3-98a

2a(4a^2-49) = 8x^3-98a

2a(4a^3-49a) = 8a^4-98a^2

(2a-7)x(2a+7)
= 2a^2-7^2
= 2^2a^2-7^2
= 4a^2-7^2
= 4a^2-49
Here, multiplication can be transformed into the difference of squares using the rule: (a-b)(a+b) = a^2-b^2

2(2a-7)(2a+7) =
(4a-14)(2a+7)
= 8a^2+28a-28a-98
= 8a^2-98

2a(2a-7)(2a+7)
= (4x^2-14a)(2a+7)
= 8a^3+28a^2-28a^2- 98x
= 8a^3-98a

Answer 2

A. 2(4a^3 - 49a)

In this case, you would simply multiply the numbers and leave the a value and exponents alone.

B. 2a(4a^2 - 49)

First, you would distribute(multiply) 2 with the numbers inside the parentheses just like you did for answer A. Then, you would distribute a with the other a values inside the parentheses, you would add this values instead of multiplying it.

F. 2a(2a - 7)(2a + 7)

You would distribute 2a inside the FIRST set of parentheses just like you did before. Then multiply that set of parentheses with the other set of parentheses.

Explanation: