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How many moles of oxygen O2 are consumed per every 50 moles of CO2 that are produced during the combustion of ethane C2H6?

User Felvhage
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Answer:

The balanced chemical equation for the combustion of ethane (C2H6) is:

C2H6 + O2 → CO2 + H2O

According to the stoichiometry of the balanced equation, 1 mole of C2H6 reacts with 3 moles of O2 to produce 2 moles of CO2. Therefore, the ratio of moles of O2 consumed to moles of CO2 produced is:

3 mol O2 / 2 mol CO2

To determine how many moles of O2 are consumed per every 50 moles of CO2 produced, we can set up a proportion:

3 mol O2 / 2 mol CO2 = x mol O2 / 50 mol CO2

Cross-multiplying and solving for x, we get:

x = (3 mol O2 / 2 mol CO2) x 50 mol CO2 = 75 mol O2

Therefore, 75 moles of O2 are consumed per every 50 moles of CO2 produced during the combustion of ethane.

Step-by-step explanation:

User Andre Guirard
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