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How many milliliters of Sulphur dioxide are formed when 12. 5g of iron sulphide ore (pyrite) reacts with oxygen according to the equation at STP? 4FeS2+1102=2Fe2O3+8SO2​ pls guys
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How many milliliters of Sulphur dioxide are formed when 12. 5g of iron sulphide ore (pyrite) reacts with oxygen according to the equation at STP?

4FeS2+1102=2Fe2O3+8SO2​
pls guys

User Margusholland
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1 Answer

7 votes

Answer:

so the mass of sulphur dioxide = 0.208334 × 22.4 L = 4.6666816 L = 4666.6816 ml Therefore the volume of sulphur dioxide is 4666.6816 ml .

Step-by-step explanation:

User UndergroundFox
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