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Help again asapppppp

Help again asapppppp-example-1
User Datt Patel
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4 votes

Answer:


\mathrm{y\:=\:(3)/(2)x\:+\:7}

Explanation:

To find the equation of a line parallel to -4y = 32 - 6x, we first need to rewrite this equation in slope-intercept form, y = mx + b, where m is the slope and b is the y-intercept.

-4y = 32 - 6x

Divide both sides by -4:

y = -8 + (3/2)x

So the slope of this line is 3/2. Since we want a line parallel to this one, it will have the same slope of 3/2.

Now we can use the point-slope form of a linear equation to find the equation of the line that passes through (0,7) with a slope of 3/2:

y - y1 = m(x - x1)

where m = 3/2 and (x1,y1) = (0,7)

y - 7 = (3/2)(x - 0)

Simplifying:

y - 7 = (3/2)x

y = (3/2)x + 7

So the equation of the line parallel to -4y = 32 - 6x that passes through the point (0,7) is y = (3/2)x + 7.

User GnomeDePlume
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