Question

Find the value of the expression below.log4 3 + log4 8 - log4 6A.1B.3C.0D.2

Answer 1

Given:

`log_43+log_48-log_46`

To Determine: The value of the given expression

Solution

Let us apply the logarithm rule below

`\begin{gathered} logA+logB=log(A* B) \\ So \\ log_43+log_48=log_4(3*8)=log_424 \\ log_43+log_48-log_46=log_424-log_46 \end{gathered}`

Applying the rule below again

`\begin{gathered} logA-logB=log(A/ B) \\ So, \\ log_424-log_46=log_4(24/6)=log_44 \end{gathered}`

And finally applying the rule below

`\begin{gathered} log_aa=1 \\ Then \\ log_44=1 \end{gathered}`

Hence, the solution of the given expression is 1, OPTION A