Question

find the value of n so that the expression is a perfect square trinomial and then factor the trinomial. x^2+10x+n

Answer 1

Answer: the answer is (x + 5)^2

Explanation:

Answer 2

From the problem, we have :

`x^2+10x+n`

To make it a perfect square trinomial, we will use the formula :

`n=((b)/(2a))^2`

and we can factor the trinomial as :

`(x+(b)/(2a))^2^{}`

a = 1 and b = 10

so n will be :

`((b)/(2a))^2=((10)/(2*1))^2=5^2=25`

The value of n is n = 25

and the factor of the trinomial will be (x + 5)^2