Question

A wallet contains 23 bills. All the bills are $1 bills and $5 bills. There are 7 more $1 bills than $5 bills. How much money does the wallet contain?

Answer 1

Explanation:

Let's say x is the number of $1 bills and y is the number of $5 bills. We know that:

x + y = 23

x = y + 7

We can use rearrange the second equation and add them together to find x. Then, we can plug x into any one of our equations to find y and calculate how much money is in the wallet.

x + y = 23

x - y = 7

2x = 30

x = 15 $1 bills

15 = y + 7

y = 8 $5 bills

15 * $1 + 8 * $5 = $15 + $40 = $55

Hope this helps!

Answer 2

$55

Explanation:

You want to know the amount of money represented by 23 bills that are $1 or $5 bills when there are 7 more $1 bills than $5 bills.

Excess

If we remove the extra $1 bills from consideration, we have 23 -7 = 16 bills that are equal numbers of $1 and $5 bills. There are 8 of each, so their value is ...

8($1 +$5) = $48

Adding back the $7 in ones, we have 23 bills worth $55.

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