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In a population of adult giraffes the frequency of individuals with AA genotype is 0.64 Calculate tge frequency of individuals with Aa genotype ?

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To calculate the frequency of individuals with the Aa genotype in a population of giraffes with a frequency of AA individuals at 0.64, we need to use the Hardy-Weinberg equilibrium formula.

The formula for the frequency of the Aa genotype is:

2pq = Aa genotype frequency

where p is the frequency of one allele (in this case, "A"), and q is the frequency of the other allele (in this case, "a").

Using the formula, we first need to find the frequency of the "A" allele:

p² + 2pq + q² = 1

Given that the frequency of AA individuals is 0.64, we know that p² = 0.64. Therefore, p = 0.8.

Next, we can solve for q:

p + q = 1

0.8 + q = 1

q = 0.2

Now we can calculate the frequency of the Aa genotype:

2pq = 2(0.8)(0.2) = 0.32

So the frequency of individuals with the Aa genotype is 0.32.
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