Question

Write the removeevens() function, which receives a vector of integers as a parameter and returns a new vector of integers containing only the odd numbers from the original vector. the main program outputs values of the returned vector. hint: if the original vector has even numbers, then the new vector will be smaller in length than the original vector and should have no blank element. ex: if the vector passed to the removeevens() function is [1, 2, 3, 4, 5, 6, 7, 8, 9], then the function returns and the program output is: [1, 3, 5, 7, 9] ex: if the vector passed to the removeevens() function is [1, 9, 3], then the function returns and the program output is: [1, 9, 3]

main.py 1 def remove evens(nums): 2 # Type your code here. 3 4 if __name__ ==' ___main___':
5 nums = [1, 2, 3, 4, 5, 6, 7, 8, 9] 6 result = remove_evens(nums) 7 8 print(result)

Answer 1

def remove_evens(nums):

# Create an empty list to hold the odd numbers

odds = []

# Loop through the input list and check if each number is odd

for num in nums:

if num % 2 != 0:

odds.append(num)

# Return the list of odd numbers

return odds

if __name__ == '__main__':

nums = [1, 2, 3, 4, 5, 6, 7, 8, 9]

result = remove_evens(nums)

print(result)

Step-by-step explanation:

In this implementation, we first create an empty list called odds to hold the odd numbers. We then loop through the input list nums, checking if each number is odd using the modulus operator (%). If the number is odd, we append it to the odds list.

Finally, we return the odds list, which contains only the odd numbers from the input list. In the main program, we pass the input list [1, 2, 3, 4, 5, 6, 7, 8, 9] to the remove_evens() function, and print the resulting list [1, 3, 5, 7, 9].