Answer:
We can use Ohm's law to determine the maximum voltage that can be safely applied to the bulb. Ohm's law states that:
V = IR
where V is the voltage, I is the current, and R is the resistance of the bulb.
In this case, the resistance of the bulb is 7 Ω, and the maximum current rating is 10 A. Substituting these values into the equation, we get:
V = (10 A)(7 Ω) = 70 V
Therefore, the maximum voltage that can safely be applied to the bulb is 70 V. Any voltage higher than this may cause the bulb to overheat and fail.