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14. 3 moles of methane (CH4 ) burns completely, find the grams of H2O would be produced

User Borisdj
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Answer: 108.09 g

Step-by-step explanation:

The balanced chemical equation for the combustion of methane is:

CH4 + 2O2 → CO2 + 2H2O

From the equation, we can see that 1 mole of CH4 produces 2 moles of H2O.

So, 3 moles of CH4 will produce:

3 moles CH4 × 2 moles H2O / 1 mole CH4 = 6 moles H2O

To find the mass of 6 moles of H2O, we need to use the molar mass of H2O, which is:

2 × (1.008 + 15.999) = 18.015 g/mol

So, the mass of 6 moles of H2O is:

6 moles H2O × 18.015 g/mol = 108.09 g

Therefore, 3 moles of CH4 will produce 108.09 g of H2O.

User Ophir Radnitz
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