Question

After rubbing two balloons against a sweater, each are held 0.75 meters apart. One balloon has a charge of 2.6 E−6 C. The other balloon has a charge of 2.2 E−7 C. Calculate the electrical force between them.

Remember to identify all data (givens and unknowns), list equations used, show all your work, and include units and the proper number of significant digits to receive full credit.

Answer 1

The electrical force between two balloons is 67.5N.

Step-by-step explanation:

There are two charged balloons, let's say a and b.

The charge on the balloon a = C

The charge on the balloon b = C

Both balloons are 1 cm apart; it means that the distance r between the balloon a and the balloon b is 0.01 m (since 1 cm = 0.01 m).

We need to find the electrical force between them. By using the Coulomb's law, the magnitude of the electrical force between both the balloon is given as follows:
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Hence, the electrical force between two balloons is 67.5N (three significant figures).

Answer 2

Given:

Distance between the balloons (r) = 0.75 m

Charge on balloon 1 (q1) = 2.6 E−6 C

Charge on balloon 2 (q2) = 2.2 E−7 C

Electric constant (k) = 8.99 × 10^9 N·m^2/C^2

Unknown:

Electrical force (F) between the two balloons

The equation for the electrical force between two point charges is:

F = k * (q1*q2)/r^2

Substituting the given values, we get:

F = (8.99 × 10^9 N·m^2/C^2) * ((2.6 E−6 C) * (2.2 E−7 C))/(0.75 m)^2

F = 4.16 × 10^-6 N

Therefore, the electrical force between the two balloons is 4.16 × 10^-6 N.

Step-by-step explanation: