Answer:
The molar mass of BeSO4 is:
9 + 32 + (4x16) = 137 g/mol
To calculate the volume of a 9 M solution containing 90 grams of BeSO4, we can use the formula:
moles = mass / molar mass
moles = 90 g / 137 g/mol
moles = 0.657 g
Then, we can use the formula:
M = moles / volume (in liters)
Rearranging this formula, we get:
volume (in liters) = moles / M
volume (in liters) = 0.657 / 9
volume (in liters) = 0.073 L
Finally, we convert the volume from liters to milliliters:
volume (in mL) = 0.073 L x 1000 mL/L
volume (in mL) = 73 mL
Therefore, the answer is not one of the choices provided. The closest option is C) 77 mL.